[Linux manuál]
Návod, kniha: Linux Programmer's Manual
The obsolete function memalign() allocates size bytes and returns
a pointer to the allocated memory. The memory address will be a multiple of
boundary, which must be a power of two.
The obsolete function valloc() allocates size bytes and returns a
pointer to the allocated memory. The memory address will be a multiple of the
page size. It is equivalent to memalign(sysconf(_SC_PAGESIZE),size).
For all three routines, the memory is not zeroed.
posix_memalign() returns zero on success, or one of the error values
listed in the next section on failure. Note that errno is not set.
posix_memalign() verifies that alignment matches the requirements
detailed above. memalign() may not check that the boundary
parameter is correct.
POSIX requires that memory obtained from posix_memalign() can be freed
using free(). Some systems provide no way to reclaim memory allocated
with memalign() or valloc() (because one can only pass to
free() a pointer gotten from malloc(), while e.g.
memalign() would call malloc() and then align the obtained
value). GNU libc allows memory obtained from any of these three routines to be
reclaimed with free().
GNU libc malloc() always returns 8-byte aligned memory addresses, so
these routines are only needed if you require larger alignment values.
Everybody agrees that memalign() is declared in <malloc.h>.
According to SUSv2, valloc() is declared in <stdlib.h>. Libc4,5 and
glibc declare it in <malloc.h> and perhaps also in <stdlib.h>
(namely, if _GNU_SOURCE is defined, or _BSD_SOURCE is defined, or, for glibc,
if _XOPEN_SOURCE_EXTENDED is defined, or, equivalently, _XOPEN_SOURCE is
defined to a value not less than 500).
posix_memalign, memalign, valloc: Přiřaďte zarovnanou paměť
Originální popis anglicky: posix_memalign, memalign, valloc - Allocate aligned memoryNávod, kniha: Linux Programmer's Manual
STRUČNĚ
#define _XOPEN_SOURCE 600 #include <stdlib.h>int posix_memalign(void **memptr, size_t alignment, size_t size);#include <malloc.h>void *valloc(size_t size); void *memalign(size_t boundary, size_t size);
POPIS / INSTRUKCE
The function posix_memalign() allocates size bytes and places the address of the allocated memory in *memptr. The address of the allocated memory will be a multiple of alignment, which must be a power of two and a multiple of sizeof(void *).NÁVRATOVÁ HODNOTA
memalign() and valloc() return the pointer to the allocated memory, or NULL if the request fails.CHYBY / ERRORY
- EINVAL
- The alignment parameter was not a power of two, or was not a multiple of sizeof(void *).
- ENOMEM
- There was insufficient memory to fulfill the allocation
request.
NOTES
On many systems there are alignment restrictions, e.g. on buffers used for direct block device I/O. POSIX specifies the pathconf(path,_PC_REC_XFER_ALIGN) call that tells what alignment is needed. Now one can use posix_memalign() to satisfy this requirement.DOSTUPNOST
The functions memalign() and valloc() have been available in all Linux libc libraries. The function posix_memalign() is available since glibc 2.1.91.ODPOVÍDAJÍCÍ
The function valloc() appeared in 3.0 BSD. It is documented as being obsolete in BSD 4.3, and as legacy in SUSv2. It no longer occurs in SUSv3. The function memalign() appears in SunOS 4.1.3 but not in BSD 4.4. The function posix_memalign() comes from POSIX 1003.1d.HEADERS
Everybody agrees that posix_memalign() is declared in <stdlib.h>. In order to declare it, glibc needs _GNU_SOURCE defined, or _XOPEN_SOURCE defined to a value not less than 600.SOUVISEJÍCÍ
brk(2), getpagesize(2), free(3), malloc(3)| 2003-08-22 | GNU |