Originální popis anglicky:
expm1, expm1f, expm1l - exponential minus 1
Návod, kniha: Linux Programmer's Manual
#include <math.h>
double expm1(double x);
float expm1f(float x);
long double expm1l(long double x);
Link with -lm.
expm1(x) returns a value equivalent to `exp (
x) -
1'. It is computed in a way that is accurate even if the value of
x is
near zero--a case where `exp (
x) - 1' would be inaccurate due to
subtraction of two numbers that are nearly equal.
BSD, C99. The float and the long double variants are C99 requirements.
exp(3),
log(3),
log1p(3)
