expm1, expm1f, expm1l: exponenciální mínus 1

Originální popis anglicky: expm1, expm1f, expm1l - exponential minus 1

Návod, kniha: Linux Programmer's Manual

STRUČNĚ

#include <math.h>
 
double expm1(double x);
 
float expm1f(float x);
 
long double expm1l(long double x);
 

Link with -lm.

POPIS / INSTRUKCE

expm1(x) returns a value equivalent to `exp ( x) - 1'. It is computed in a way that is accurate even if the value of x is near zero--a case where `exp ( x) - 1' would be inaccurate due to subtraction of two numbers that are nearly equal.

ODPOVÍDAJÍCÍ

BSD, C99. The float and the long double variants are C99 requirements.

SOUVISEJÍCÍ

exp(3), log(3), log1p(3)